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Comment on Introduction to Algebra
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If x is the number on the
so i got 3x = 10 and x = 10/3 but why do we have to do this: 5+2x=5+20/3=35/3
or 15−x=15−10/3=35/3=11 2/3
Your solution is kind of
Your solution is kind of correct.
You concluded that x = 10/3, but 10/3 doesn't satisfy the condition that x is BETWEEN 5 and 15.
Having said that, I can see what you're trying to do.
You recognized that there are 10 units between 5 and 15.
You then divided those 10 units into 3 equal portions of 10/3 units each.
From here, all you need to do is recognize that x is 10/3 units less than 10.
In other words, x is 11 2/3
To help understand the alternative solutions, you can start by checking out my solution here: https://gre.myprepclub.com/forum/if-x-is-the-number-on-the-number-line-b...
Cheers, Brent
I received this question from
The Sargon Corporation offers an optional stock-option buy in program to its employees. Of the employees with salaries greater than or equal to $100K, 85% choose to participate in this plan. Of the employees with salaries less than $100K, 77% choose to participate in this plan. Which of the following could be the total number of employees? Answer choices below:
100
200
350
460
525
640
750
880
For this question what I specifically did was convert that 85(x)/100 , where is the total people who went with the plan into 17(x)/20 and same thing for the 77(x)/100. I then looked at the choices and broke each answer choice in half so for 200 it would become 100 and 100 and plugged this into the equation 17(x)/20 and 77(x)/100 to see if they would work. I did this for each answer choice and got only 200 and 640 as the answers but the complete list of answers are 200,460,640, and 880. Also please clarify if my approach is right for could be problems: As a could be problem if we find one answer choice that works then we would select that choice. But does this also mean we may run into conditions that don't work, but yet that answer choice may still be correct. For example in this problem I thought 460 does not work since I break it down into 230 and 230 even it did not go evenly into the fractions, but yet it is a correct answer.
Hey Ravin,
Hey Ravin,
Tricky question!
Here's my full solution: https://gre.myprepclub.com/forum/the-sargon-corporation-offers-an-option...
Cheers, Brent
https://gmatclub.com/forum/in
For this question I solved it via algebra and got answer choice D xy /(y+x), my question is however on the answer choices, like why cant someone choose r = x+y and get it right as well?
Question link: https:/
Question link: https://gmatclub.com/forum/in-an-electric-circuit-two-resistors-with-res...
The goal is to simplify 1/r = 1/x + 1/y
Notice that, if 1/a = 1/b, Then we can also say that a = b
This works because we can easily cross multiply to get a = b
The same does not hold true for 1/r = 1/x + 1/y, since we don't have a single fraction equaling another single fraction.
We can quickly demonstrate why the equation 1/r = 1/x + 1/y does not simplify to be r = x + y by testing some numbers.
For example, we know that 1/2 = 1/4 + 1/4
In other words, when r = 2, x = 4 and y = 4, the equation 1/r = 1/x + 1/y holds true.
However, when we plug these numbers into the equation r = x + y, we get 2 = 4 + 4, which is not true.
Thanks very much.. I find
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