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Comment on Power with Binomial Product
Could you please explain why
Your factoring is not quite
Your factoring is not quite right.
When we expand (x+2)(x-1), we get x^2 + x - 2 (not x^2 + x - 3)
(x+4)(x-3)=x^2-3x+4x-12
=x^2+x-12
add +9 to both sides we end up with
x^2+x-3 0
16^(x^2+x-3) 16^0
1 1
answer is c
Great!
Great!
That was tricky.
Indeed!
Indeed!
Great question. It's
I hope this kind of question
It's definitely a tricky one!
It's definitely a tricky one!!
If x^2+x-3 = (x-3)(x+1) = 0
then place x either 3 or -1 to (x+4)(x-3) i got QA = 0 or -12 so why i cannot answer D
Be careful. x²+x-3 does not
Be careful. x²+x-3 does not equal (x-3)(x+1)
If we take (x-3)(x+1) and expand it (using the FOIL method), we get: x²-2x-3 (not x²+x-3)
As mentioned in the video, we cannot factor the expression x²+x-3
Cheers,
Brent
These Quantitative
You're right; sometimes we
You're right; sometimes we need to use the given information immediately, and sometimes we use the given information later on.
Whether you use the given information at the beginning of the solution or near the end will depend on the nature of the question.
This scenario plays out in most Quantitative Comparison questions, which you'll find links to throughout the course (in the Reinforcement Activities boxes)
Cheers,
Brent