Question: Wind Chill Factor - Question II

Comment on Wind Chill Factor - Question II

I am sorry this question sounds a little too simple- but I got confused with the term-"at most"-I interpreted that to mean the coldest or at most it is minus 5, so the lesser range would be warmer or lower than that which would be 0 or less. So, I answered with the opposite side.
greenlight-admin's picture

That's understandable. However, when it comes to temperature, the higher/more/greater/bigger the number, the hotter the temperature.

can you please explain , if temperature is at most -5 degrees , why are we taking negative side of table . ??
greenlight-admin's picture

If the temperature is AT MOST -5 degrees, then the temperature must be LESS THAN OR EQUAL TO -5 degrees.
So for example the temperature COULD be -10 or -5, or -22 or -31 or....

Does that help?

Cheers,
Brent

I have a question regarding the solution. The way you have explained it seems that you are assuming ranges. For example, when the wind is 5mph you derived the answer by taking the range between -15 and -20. If I encounter a question like this on the test should I also consider the value as ranges as I thought these values applied to one single perceived temperature
greenlight-admin's picture

Great question.

We're examining ranges, because the question tells us that "the temperature is AT MOST -5 degrees Fahrenheit"

In other words, we're told that the temperature could be anywhere in the range of temperatures from -5 all the way down to super low low low temperatures. This is why I highlighted those various temperature in yellow.

Also, when we examine the scenario when the wind is 5mph, we're looking for an air temperature that would result in a perceived temperature of -29 degrees.

Unfortunately, there is no air temperature (when combined with a wind speed of 5 mph) that yields a perceived temperature of exactly -29 degrees.

We know that an air temperature of -15 degrees yields a perceived temperature of -28 degrees, and we know that an air temperature of -20 degrees yields a perceived temperature of -34 degrees.

Since -29 degrees is between -28 degrees and -34 degrees, this means the air temperature must be between -15 and -20

Does that help?

Cheers,
Brent

Hey, it is a very nice question and I don't try to disparage this question but I have a problem with the ranges. I saw that someone else also had the same problem.
Looking at the real-world scenario, it is likely that there will be ranges and at some point, it will be -29 degrees, but in the test, how can I know that it is viewed as ranges? Can it be a question like that in the test where it did not mention that it uses ranges?
greenlight-admin's picture

Great question.
The problem is, we could never create a chart that includes every possible temperature (e.g., -13.42125 degrees) and every possible speed (e.g., 27.76 mph.), so, unless you're given values that match those in the table, you're going to have to use ranges.

Similarly, we might create a table that converts Celsius to Fahrenheit.
The table might look something like this:

C | F
-20 | -4
-10 | 14
0 | 32
10 | 50
20 | 68

For this table, a legitimate GRE question might ask you to find the Celsius equivalent to 21 degrees Fahrenheit, and the answer would be given as ranges.

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