Lesson: Introduction to Algebra

Comment on Introduction to Algebra

It's really awesome
greenlight-admin's picture

Thanks!

Crazy man! When you asked what algebra is I skipped the vid ahead (who doesn't know what it is right?) but ended up going back to the start. I've taken tons of math courses (electrical engineer) but never thought what it means to say 3x+7x=10x. I would've just said 3 x's plus 7 x's is 10x's. Insightful!!
greenlight-admin's picture

Glad you like it!

If x is the number on the number line between 5 and 15 that is twice as far from 5 as from 15, then x is

so i got 3x = 10 and x = 10/3 but why do we have to do this: 5+2x=5+20/3=35/3

or 15−x=15−10/3=35/3=11 2/3
greenlight-admin's picture

Your solution is kind of correct.
You concluded that x = 10/3, but 10/3 doesn't satisfy the condition that x is BETWEEN 5 and 15.

Having said that, I can see what you're trying to do.
You recognized that there are 10 units between 5 and 15.
You then divided those 10 units into 3 equal portions of 10/3 units each.
From here, all you need to do is recognize that x is 10/3 units less than 10.
In other words, x is 11 2/3

To help understand the alternative solutions, you can start by checking out my solution here: https://gre.myprepclub.com/forum/if-x-is-the-number-on-the-number-line-b...

Cheers, Brent

I received this question from a Magoosh study and wanted to see whats the easiest way to approach it:

The Sargon Corporation offers an optional stock-option buy in program to its employees. Of the employees with salaries greater than or equal to $100K, 85% choose to participate in this plan. Of the employees with salaries less than $100K, 77% choose to participate in this plan. Which of the following could be the total number of employees? Answer choices below:

100
200
350
460
525
640
750
880

For this question what I specifically did was convert that 85(x)/100 , where is the total people who went with the plan into 17(x)/20 and same thing for the 77(x)/100. I then looked at the choices and broke each answer choice in half so for 200 it would become 100 and 100 and plugged this into the equation 17(x)/20 and 77(x)/100 to see if they would work. I did this for each answer choice and got only 200 and 640 as the answers but the complete list of answers are 200,460,640, and 880. Also please clarify if my approach is right for could be problems: As a could be problem if we find one answer choice that works then we would select that choice. But does this also mean we may run into conditions that don't work, but yet that answer choice may still be correct. For example in this problem I thought 460 does not work since I break it down into 230 and 230 even it did not go evenly into the fractions, but yet it is a correct answer.
greenlight-admin's picture

Hey Ravin,

Tricky question!
Here's my full solution: https://gre.myprepclub.com/forum/the-sargon-corporation-offers-an-option...

Cheers, Brent

https://gmatclub.com/forum/in-an-electric-circuit-two-resistors-with-resistances-x-and-144899.html

For this question I solved it via algebra and got answer choice D xy /(y+x), my question is however on the answer choices, like why cant someone choose r = x+y and get it right as well?
greenlight-admin's picture

Question link: https://gmatclub.com/forum/in-an-electric-circuit-two-resistors-with-res...
The goal is to simplify 1/r = 1/x + 1/y

Notice that, if 1/a = 1/b, Then we can also say that a = b
This works because we can easily cross multiply to get a = b

The same does not hold true for 1/r = 1/x + 1/y, since we don't have a single fraction equaling another single fraction.
We can quickly demonstrate why the equation 1/r = 1/x + 1/y does not simplify to be r = x + y by testing some numbers.

For example, we know that 1/2 = 1/4 + 1/4
In other words, when r = 2, x = 4 and y = 4, the equation 1/r = 1/x + 1/y holds true.
However, when we plug these numbers into the equation r = x + y, we get 2 = 4 + 4, which is not true.

Thanks very much.. I find very interesting and useful materials here. Well done!
greenlight-admin's picture

Thanks! I'm glad you like them.

Have a question about this video?

Post your question in the Comment section below, and a GRE expert will answer it as fast as humanly possible.

Change Playback Speed

You have the option of watching the videos at various speeds (25% faster, 50% faster, etc). To change the playback speed, click the settings icon on the right side of the video status bar.

How do the Reinforcement Activities work?

Free “Question of the Day” emails!