Lesson: Distance Between Two Points

Comment on Distance Between Two Points

root 34 has come another method root20 i.e 2root5 how 2 solutions??can you explain please
greenlight-admin's picture

At 1:15 in the video, we find that the distance between (-2, -4) and (3, -1) is √34

At 2:30 in the video, we find that the distance between (2, -4) and (4, 0) is √20

So, we are finding the distances between two different sets of points. This is why we arrive at 2 different distances.

greenlight-admin's picture

At 1:15 in the video, we find that the distance between (-2, -4) and (3, -1) is √34

At 2:30 in the video, we find that the distance between (2, -4) and (4, 0) is √20

So, we are finding the distances between two different sets of points. This is why we arrive at 2 different distances.

can you please explain 2nd question, given below to the video
http://gre.myprepclub.com/forum/topic1885.html

expecting the explaination, thanks in advance.
greenlight-admin's picture

I've added my solution (with graphics) here: http://gre.myprepclub.com/forum/topic1885.html#p9785

Hello Brent,

For the following question, when using distance formula, I arrive at an equation ((b+2)^2)^1/2=3. Why should not we use exponent rule directly here and multiply 2*1/2 in the exponent, which gives only one solution (b=1) ? Please advise me

http://gre.myprepclub.com/forum/the-distance-from-b-2-to-2576.html

Thanks :)
greenlight-admin's picture

Question link: http://gre.myprepclub.com/forum/the-distance-from-b-2-to-2576.html

Good question!

When applying the power of a power law to solve an equation, we must be careful when one of those powers represents a root, because we can lose a potential solution in the process.

In this case, it's better to stick with the square root rather than rewrite the root as a power.

Your equation is in the form √(x²) = 3

From this, we can conclude that x² must equal 9, which means EITHER x = 3 OR x = -3. When we plug these two possible values of x into the original equation, we see that they both satisfy the equation.

NOTE: we get TWO solutions because, when we SQUARE any number (positive or negative), the result is always greater than or equal to zero. For example, 5² = 25 and (-5)² = 25. So, there are TWO numbers, that when squared, yield a result of 25.

However, if we first simplify √(x²), we lose out on one of those solutions.

Thanks Brent. I'll watch out not to use power law when we have a sq root over an even power in order to get all solutions to the equation.

How did you get the distance to be 5 and 3 when i count it,i get 6 and 4
greenlight-admin's picture

For the horizontal distance, we get: 3 - (-2) = 5
For the vertical distance, we get: (-1) - (-4) = 3

What calculations did you perform to get 6 and 4?

Cheers,
Brent

I didn't calculate. I just counted the number of digits between 3 and -2. i didn't even know calculations were involved.
Please why are you subtracting?
greenlight-admin's picture

First off, counting the number of integers between 3 and -2 won't tell you the distance between 3 and -2

For example, what is the distance between 5 and 6?
Applying your technique, we'd have to say that the distance is zero, since there are no integers BETWEEN 5 and 6.

Instead, the distance between 5 and 6 = 6 - 5 = 1

In the distance formula, we subtract x-values and y-values.

To understand why we do this, let's examine the number line.

For example, what is the distance between 8 and 2 on the number line?
Well, the distance = 8 - 2 = 6

Likewise, the distance between 5 and -3 = 5 - (-3) = 8

Does that help?

Cheers,
Brent

What about the third example? Isn't the horizontal distance spose to b 4-(-4)
greenlight-admin's picture

I believe you're referring to the example at 2:45 in the above video.
The two points are (4, 0) and (2, -4)

To find the horizontal distance, we subtract the x-values.
To find the vertical distance, we subtract the y-values.

So, the horizontal distance = 4 - 2 = 2

Does that help?

Cheers,
Brent

This is great! Thanks

https://gre.myprepclub.com/forum/in-the-coordinate-plane-points-a-b-and-c-d-are-2441.html
In your solution here,you didn't involve the square root in your distance between 2 points formula
greenlight-admin's picture

Question link: https://gre.myprepclub.com/forum/in-the-coordinate-plane-points-a-b-and-...

I didn't have a solution posted for this question :-)

However, I do now (and it has square roots!!): https://gre.myprepclub.com/forum/in-the-coordinate-plane-points-a-b-and-...

Cheers,
Brent

The distance from (b,2) to (-2,2) is 3
QA =b
QB =0

A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.


I would be highly appreciated if I explain it in detail how b became b= 1 , b= -5 because I substitute at distance point formula the square root one but it didn't work.
Thanks
greenlight-admin's picture

hi brent! I had a question on your solution for this Q: https://gre.myprepclub.com/forum/p-q-and-r-are-three-points-in-a-plane-and-r-does-not-lie-1885.html

Why is the answer not 2 points? As shown in your diagram, if P and Q were centers of circles that have equal radii, there are then two points which could R, which is not on the PQ line, So couldnt' the answer be C?
greenlight-admin's picture

Solution link: https://gre.myprepclub.com/forum/p-q-and-r-are-three-points-in-a-plane-a...

The only condition on point R is that it can't lie on line PQ.
This still leaves infinitely many possible places to put point R.
However, the question isn't asking us about point R; it's basically asking us to determine the number of points the blue line and red line have in common.

Does that help?

Have a question about this video?

Post your question in the Comment section below, and a GRE expert will answer it as fast as humanly possible.

Change Playback Speed

You have the option of watching the videos at various speeds (25% faster, 50% faster, etc). To change the playback speed, click the settings icon on the right side of the video status bar.

Let me Know

Have a suggestion to make the course even better? Email us today!

Free “Question of the Day” emails!