Whenever you encounter a quantitative question with answer choices, be sure to SCAN the answer choices __before__ performing any calculations. In many cases, the answer choices provide important clues regarding how to best solve the question.

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## Comment on

3 Flasks## I did find the solution in

## Unfortunately, that approach

Unfortunately, that approach is incorrect; it just happened to work with the numbers given in the question.

If we were to change the question so that one flask was 1/6 full, one flask was 1/7 full, and one flask was 1/12, the correct answer would still be 1/6. However, your approach would yield an incorrect answer.

## you mentioned in other video

bigger denominator = small value(as whole)and vice versa then here how did you take 1/6 and 1/8 as a smallest flasks and 1/12 as largest? 1/6 = 0.167, 1/8 = 0.125,

1/12 = 0.8333 doesn't that make 1/6 largest and 1/6 and 1/8 smallest?

## Those examples (from https:/

Those examples (from https://www.greenlighttestprep.com/module/gre-arithmetic/video/1067) is different from this question.

In that other video lesson, I say that 113/400 is greater than 113/401, because the denominator 400 is less than the other denominator (401).

When we compare the 3 flasks (which are 1/12 full, 1/8 full and 1/6 full), we aren't comparing fractions. We are trying to determine which flask has the greatest capacity.

Think of it this way: If I pour a can of soda into a large glass, the glass becomes 1/2 full. If I pour a can of soda into an empty swimming pool, the pool becomes 1/100,000 full. Which has a greater CAPACITY? The glass or the pool.

Here's a mathematical way to look at it:

Keep in mind that the 3 flasks each contain an equal volume of water. So, let's just focus on two flasks and let:

A = the capacity of the flask that is 1/12 full

B = the capacity of the flask that is 1/8 full

Since both flasks contain an equal volume of water, we can write: 1/12 of A = 1/8 of B

In other words: (1/12)A = (1/8)B

Expand: A/12 = B/8

Cross multiply to get: 8A = 12B

Divide both sides by 8 to get: A = (3/2)B

In other words, A = 1.5B

In other words, the capacity of A is 1.5 TIMES the capacity of B.

In other words, flask A has a greater capacity than flask B.

Does that help?

## How are you able to label the

## x = the VOLUME of water that

x = the VOLUME of water that's initially poured into each flask.

We're told that "EQUAL volumes of water were poured into the 3 empty flasks," so we can use the variable x to describe the VOLUME of water in each flask.

## "if 1/2 of the water from

## I'm not sure I agree with the

I'm not sure I agree with the assessment that "it allows for the interpretation that 1/2 of the water from each flask's capacity is to be taken"

The instructions say "Then 1/2 of the water from each of the two smallest flasks is then poured..."

Since we're removing half of the water, the flask's capacity doesn't really come into play.

That said, we can agree to disagree :-)

## Hi, This is how I solved it.

I assumed volume in each flask is 2 (easy number)

So total volumes of each of the flasks must be - 12,16 and 24 respectively.

Then as half the water from two of the smallest flasks go to the largest - 1 and 1 is removed. And volume of largest flask become 4.

Finally, 4/24 = 1/6.

Is this a fine approach?

## Excellent approach!

Excellent approach!

## How did SSS get the values 12

## SS started by saying each

SS started by saying each flask contained 2 units of water.

We're told that the first flask is 1/6 full.

So, the CAPACITY of the first flask must be 12 units (since 2/12 = 1/6)

We're also told that the second flask is 1/8 full.

So, the CAPACITY of the second flask must be 16 units (since 2/16 = 1/8)

Finally, we're told that the third flask is 1/12 full.

So, the CAPACITY of the second flask must be 24 units (since 2/24 = 1/12)

Does that help?

Cheers,

Brent

## I did the exact measure, and

## Perfect!

Perfect!

## Hi Brent,

For this could please help me in understanding the half water removal and adding it into large flask

how did she get 4/24

and also in the video at last how you told that it got doubled.

Thanks

## If we say each flack

If we say each flack ORIGINALLY contains 2 units of water, then:

The CAPACITY of the smallest flask is 12 units (since 2/12 = 1/6)

The CAPACITY of the middle flask must be 16 units (since 2/16 = 1/8)

The CAPACITY of the largest flask must be 24 units (since 2/24 = 1/12)

At this point, we're told to pour HALF of the water from each of the two smaller containers into the largest container.

Since each flask originally contained 2 units of water, we will pour 1 unit of water from EACH of the two smaller containers.

So, 1 unit of water is poured from the smallest flask into the largest flask.

And 1 unit of water is poured from the middle flask into the largest flask.

Since we're adding 2 units of water to the largest flask (which ORIGINALLY contained 2 units of water), the largest flask now contains 4 units of water.

Does that help?

Cheers,

Brent

## ss's method is easy and quick

## Agreed!

Agreed!

## Hi Brent,

I solved it as this : Since equal volumes were poured in all 3 flasks, taking 1/2 of water from other two flasks is equal to taking another 1/12 of water. So the largest flask now is filled with 1/12+1/12 = 1/6 water

Is this right approach ?

Thanks :)

## Perfect approach!

Perfect approach!

## Where can i find similar

## The question doesn't really

The question doesn't really belong to a specific category of questions.

I'd loosely place it in the family of general word problems.

You will find general word problems in the Reinforcement Activities boxes of the following videos:

- https://www.greenlighttestprep.com/module/gre-word-problems/video/902

- https://www.greenlighttestprep.com/module/gre-word-problems/video/903

- https://www.greenlighttestprep.com/module/gre-word-problems/video/907

Cheers,

Brent

## This was my approach. I

## That approach works perfectly

That approach works perfectly - well done!

Cheers,

Brent

## Can you help in solving this

Taylor earns $2,500more in 6 months than Pete. If Pete gets a 10% raise, their earnings would be equal for 6months. How much money does Pete earn a year?

## GIVEN: Taylor earns $2,500

GIVEN: Taylor earns $2,500 more in 6 months than Pete.

Let P = the amount Pete makes in 6 months

So, P + 2500 = the amount Taylor makes in 6 months

GIVEN: If Pete gets a 10% raise, their earnings would be equal for 6 months.

After the 10% raise, the amount Pete earns = P + (10% of P)

= P + 0.1P

= 1.1P

This 10% increase makes their earnings EQUAL.

We can write: 1.1P = P + 2500

Subtract P from both sides: 0.1P = 2500

Solve: P = 2500/0.1 = 25,000

So, Pete presently earns $25,000 in 6 months

Cheers,

Brent

## Thank you so much

## I assumed that the other two

## Totally valid approach - nice

Totally valid approach - nice work!

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