Question: Wind Chill Factor - Question I

Can you tell me where you are having difficulties? Otherwise, I will probably just repeat the solution from the video.

Hi Tsedze,

In your solution, you are confusing the perceived temperature with the actual air temperature.

The question tells us that the perceived temperature is -20 degrees. The perceived temperatures (related to actual air temperature and wind speed) are in the boxes throughout the diagram. The actual air temperatures are listed in the top row.

Does that help?

Cheers,
Brent

Question link: https://gre.myprepclub.com/forum/qotd-7-selected-data-for-greetin-card-s...

The question: 25. In 1993 the average (arithmetic mean) price per card for all greeting cards sold was $1.25. For which of the following occasions was the number of cards sold in 1993 LESS THAN the total number of cards sold that year for occasions OTHER THAN the ten occasions shown?

We know that the TOTAL NUMBER of cards sold for ALL occasions was approximately 4.6 billion
We also know that the 10 occasions shown accounted for 3.9 billion cards
The question asks us about the number of cards sold for occasions OTHER THAN the ten occasions shown?

So, to find the number of cards sold for occasions OTHER THAN the ten occasions shown, we must subtract 3.9 billion from 4.6 billion.

Does that help?

Cheers,
Brent

Hi Goebel,

Once we conclude that the correct answer is some number between 5 degrees and 10 degrees, we must choose the answer choice that MUST include a value between 5 and 10.

So, let's consider these possible answer choices:
A) -60 and -40 degrees Fahrenheit
B) -40 and -10 degrees Fahrenheit
C) -10 and 30 degrees Fahrenheit
D) 30 and 60 degrees Fahrenheit
E) 60 and 100 degrees Fahrenheit

Among these answer choices, only C includes a value between 5 and 10, so C must be correct.

Does that help?

Cheers,
Brent