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## Comment on

“Fixing” the Denominator## I initially took root 25 and

## Sorry, which question are you

Sorry, which question are you referring to?

## I think they were referring

## Thanks kdusold!

Thanks kdusold!

So, we're referring to the question at 2:24 in the video.

Once we get to 2√50/15, we can still simplify √50 in the numerator.

√50 = √(25 x 2) = (√25)(√2) = 5√2

So, 2√50/15 = (2)(5√2)/15 = (10√2)/15 = (2√2)/3

## Can you multiply conjugate

## Yes. The technique works will

Yes. The technique works will all denominators.

## I dont understand where 10

## I believe you're referring to

I believe you're referring to what happens at 5:53 in the video.

We have 2√25

√25 = 5

So, 2√25 = (2)(√25)

= (2)(5)

= 10

Cheers,

Brent

## If all the terms in the

## The basic structure remains

The basic structure remains the same.

1) If we have (some term) + (some other term), then the conjugate is (some term) - (some other term)

2) If we have (some term) - (some other term), then the conjugate is (some term) + (some other term)

So, for example, if we have √3 + 4, then the conjugate is √3 - 4

If we have -√3 - 4, then the conjugate is -√3 + 4

Does that help?

Cheers,

Brent

## Is the best approach to the

## Question link: https:/

Question link: https://greprepclub.com/forum/if-c-and-d-are-positive-integers-and-m-is-...

Yes, testing values definitely is the best/fastest approach for that question.

Cheers,

Brent

## around 4:00 in the video the

would this not be simplified to be (10√2)/7 ?

## 15 and 5√2 are not "like

15 and 5√2 are not "like terms," so we can't combine them (in the same way that 15 - 5x does not simplify to be 10x.)

IF the expression were 15√2 - 5√2, then it would simplify to be 10√2

However, as it stands we can't simplify 15 - 5√2

For more on this, watch: https://www.greenlighttestprep.com/module/gre-powers-and-roots/video/1042