Lesson: Mean, Median and Mode

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I'm at cloud nine now! I'm a potential GRE aspirant. I find this video very useful for dummies like me to learn Maths. In a funny note, I'm also finding all GRE vocabs words to praise the tutorial. It is so useful that I was able to crack many questions easily.
greenlight-admin's picture

Thanks! Glad you like the videos,

Hi, I just want to make sure about one information about the mode, I know that if all numbers in 1 set are different from each others there will be no mode, but you have said in the e.g at 2:20 mins all of the four numbesr we will consider them as mode so we have 4 modes.
greenlight-admin's picture

In the case that all of the values are different, then we can say that there is a multi-way tie for the most common value.

So, for example, the set {2, 3, 6, 9} has four modes: 2, 3, 6 and 9


plz explain this sum
greenlight-admin's picture

You bet.
I've posted my solution here: http://greprepclub.com/forum/course-of-an-experiment-95-measurements-wer...




Sometimes i get confused to put answers in 0.1, 0.01 similar like accuracies. Can you please help me in understanding those concepts well.

Can you pl provide the soln to this - A set of 7 integers has a range of 2, an average of 3, and a mode of 3.
greenlight-admin's picture

Set A can be EITHER {2, 2, 3, 3, 3, 4, 4} OR {2, 3, 3, 3, 3, 3, 4}
Both of these sets meet the given conditions.
Can you tell me how the question is worded?

This is the link to the exact question: http://greprepclub.com/forum/a-set-of-7-integers-has-a-range-of-2-an-average-of-3-and-a-mode-of-2675.html

I was able to come to the answer. But I wasn't sure till the end. Would be nice if you could help me think through.
greenlight-admin's picture

You bet.
Here's my step-by-step solution: http://greprepclub.com/forum/a-set-of-7-integers-has-a-range-of-2-an-ave...


2 3 3 3 3 3 4 is one possible set.

Since they told mode 3 expect 1st and 7th, all member can be 3, we met mode restriction. Range has to be 2 so let 1st member be 2 and certainly 7th member will be 4.

Hi Brent,

For the following question, can we say using the logic of weighted average that the qty B is greater ? Qty A has equal weight for x and y. So average has to be in the middle of x and y. However, Qty B has 2 weights of y and 1 weight of x. So average has to be closer to y than x. Since y > x, the average from qty B has to be greater.


Also for this question, http://greprepclub.com/forum/graph-above-shows-the-frequency-distribution-of-50-integer-1805.html, 23 values <5 (median), 16 values =5, 11 values >5. More weightage in < median. So average has to be < 5.

Thanks :)
greenlight-admin's picture

Hi Vinodhini,

Question link: http://greprepclub.com/forum/x-y-3608.html
Yes, the weighted approach you describe is perfect. GREAT WORK!!

Question link: http://greprepclub.com/forum/graph-above-shows-the-frequency-distributio...

Your approach says that, since there are more values BELOW the median than there are values ABOVE the median, the average must be LESS THAN the median.

This approach can get you in trouble, because the mean (average) depends on the MAGNITUDE of the values above and below the median.

For example, if we replace one of the eleven 6's with 1,000,000 then the average of the 50 values will be greater than the median.


Hi Brent,
Thank you. Got my mistake in 2nd approach..

Hi Brent ! I wanted to ask if there is any way that i can find all the reinforcement problems in one place .Like there are very good problems that i have encountered but i tend to forget the tricks and complexity some problems involve as i have seen them only once .. but i wish to revise and go through all the problems once. Is there any such link available.
greenlight-admin's picture

Sorry, but I don't have a list of all reinforcement problems in the course. Perhaps this is something I will add in the future.

Ok np sir! Thanks for all the help !

Thank you very much!


If x=0, and y= -2, then the A seems to be greater than the answer would be D, wouldn't it?
greenlight-admin's picture

Question link: https://greprepclub.com/forum/if-x-y-3281.html

If x = 0, and y = -2, then we get:

QUANTITY A: Average = [0 + 0 + 0 + (-2) + (-2)]/5 = -0.8
QUANTITY B: Average = [0 + 0 + (-2)]/3 = -0.66666...

So, -0.8 < -0.66666..., so Quantity B is greater.

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