Question: Cable TV and Kitchenette

Comment on Cable TV and Kitchenette

Why do all that when you can clearly see that 80 % and 30 % don't add up to 100%, but instead they add up to 110%, hence, that 10% left over has to be the percentage of rooms with both things.
greenlight-admin's picture

That only works because 0% of the rooms have neither AC nor cable TV. If we were told that 3% of the rooms have neither AC nor cable TV, then the answer would not be 10%. The answer would be 13%.Also keep in mind that this question is meant to help people practice the Double Matrix method.

I think a Venn diagram is best for this Q!
greenlight-admin's picture

Venn diagrams work fine for easier questions (like this one), but they're tougher to use with harder questions. This is why I recommend the Double Matrix method for all overlapping sets questions.

I like the double matrix way very much in solving this problem and other problems.
Thanks!
greenlight-admin's picture

I like it too. It's great for organizing the information.

Hi Brent, The matrix way is Super good and easy. but how about this approach - Given that CTV +K+ both =Total

if Total is 100, then CTV =80, K=30

from above equation => 80+30+both = 100
=> 110+both =100
=> both =100-110
=> -10 but apply absolute for our interpretation to make it positive 10.
So Answer is 10

greenlight-admin's picture

Good idea, Vineet.
The only problem with your solution is that it should be: TV + K - BOTH = total
Need to subtract BOTH in order to avoid counting rooms twice.

Here's what I mean:
If room #11A has a TV AND a kitchenette, then we will be counting it once as having a TV, and counting it again as having a kitchenette. To account for this duplication, we subtract BOTH.

Thanks for correcting Brent.

Can we also use the probability (Tv and Kitchenette) from the Stats module?
greenlight-admin's picture

Great idea!

We can actually use the OR probability here.

That is: P(TV or kitchenette) = P(TV) + P(kitchenette) - P(TV and kitchenette)

IMPORTANT: The question tells us that every room has a TV, a kitchenette, or BOTH. This means there are 0 rooms that have neither a TV nor a kitchenette.
So, P(TV or kitchenette) = 1

Substitute values into the OR probability: 1 = 0.8 + 0.3 - P(TV and kitchenette)
Solve: P(TV and kitchenette) = 0.1 = 10%

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