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Comment on Range of Variable Expressions
this problem belongs to
I can assure you that I'm the
I can assure you that I'm the creator and copyright owner of this video.
If you have any doubts, you can contact Magoosh about it.
Cheers,
Brent
Now, why would you have to
Earlier in the question, we
Earlier in the question, we concluded that the range = 2x + 2y
So, once we know that x+y = 20, we must multiply both sides by 2 to get: 2x + 2y = 40
Does that help?
Cheers,
Brent
Hi,
Plz let me know if I can put values:
As the median is : x + y = 20
let x = 1 and y = 19 , 0 < x < y or 0 < 1 < 19
Now x - y = -18
and 3x + y = 22
The range from -18 to 22 = 22 - (-18) = 40
Thanks
Perfect!
Perfect!
Once we know that the median = 10, we can just plug in values for x and y to determine the range.
Cheers,
Brent
Whoops.
Not *quite* perfect. :)
You probably didn't catch the arithmetic mistake.
@useradb9cc chose suitable numbers. (Any two numbers for x and y that sum to 20 will work.)
In that post, as correctly noted, x=1, y=19, and
x-y= -18
3x+y= 22
But the range of -18 and 22 does not equal 41.
The range is
22-(-18) = (22+18) = 40
(not 41)
@useradb9cc
Good catch - thanks!!
Good catch - thanks!!
I edited useradb9cc's solution (to help minimize confusion)!
Thanks again!