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## Comment on

Introduction to Decimals## The 3rd problem linked below

Maurice entered a number into his calculator and erroneously divided the number by 0.03 instead of 0.0003, resulting in an incorrect result. Which of the following is a single operation that Maurice could perform on his calculator to correct the error?

Indicate all such operations.

A. Multiply the incorrect product by 100

B. Divide the incorrect product by 100

C. Multiply the incorrect product by 0.01

D. Divide the incorrect product by 0.01

## You're referring to this

You're referring to this question: http://greprepclub.com/forum/qotd-2-maurice-entered-a-number-into-his-ca...

Please check the link - I have now added my solution.

## for the decimals is it always

## Yes, it's always the case.

Yes, it's always the case.

## How to round off to the

for example if we have a decimal 0.16, how to round to nearest 0.05?

In ETS guide 2nd edition (page number 298 question number 16), they have asked to round to nearest 0.05

## You will never be tested on

So, here we must consider increments of 0.05, as in 0.05, 0.1, 0.15, 0.2, 0.25, 0.3, etc

Since 0.16 lies between 0.15 and 0.2, we must determine which value 0.16 is closer to.

Since 0.16 is closer to 0.15, we can say that 0.16, rounded to the nearest 0.05 is 0.15

## Suppose if number is 0.18,

Like wise 0.17 to 0.15

Am I correct?

## Yes, that's correct.

Yes, that's correct.

0.18 is closer to 0.20 than it is to 0.15, so if we're rounding to the nearest 0.05, then we'd round it to 0.20

The same goes for rounding 0.17 to 0.15

## Hi BRENT,

can you give an example video or any online source for an example of one of this type of nearest 0.05 sum? it would be helpful.

## The only example I've seen of

The only example I've seen of this kind of rounding can be found in ETS's Official Guide to the GRE - 2nd edition (page 298, question 16b).

The same question can be found in ETS's Official Guide to the GRE - 3rd edition (page 322, question 16b).

## Hi, in the ETS's official

(20/5)^2-(-2+6)^3 but the answer on the next page says 1,024. Can you please explain? thanks

## You're absolutely right.

You're absolutely right.

(20/5)^2-(-2+6)^3 = (4)^2-(4)^3

= 16 - 64

= -48

The answer of 1024 would be correct IF the question involved multiplication and not subtraction.

That is, (20/5)^2 x (-2+6)^3 = (4)^2 x (4)^3

= 16 x 64

= 1024

## thank you for clarifying!

## Can't we just use the

## Great question!

Great question!

The GRE's onscreen calculator is pretty clunky (and may even function differently from your personal calculator), so if you plan to use it on test day, be sure you know how it works. See this video: https://www.greenlighttestprep.com/module/general-gre-info-and-strategie...

Also note that the GRE can test your knowledge of the manual techniques by adding a few variables.

For example, if x and y represent single digits and (3.x)(1.2y) = 4.25, what can we conclude (if anything) about x and y?

As you can see, this kind of question reduces the effectiveness of the onscreen calculator, and relies more on your understanding of how we multiply decimals.

Cheers,

Brent

## Thanks for clarifying.

## In the first practice

I don't know if I am missing something else which should include k=2

## Question link: https:/

Question link: https://greprepclub.com/forum/k-is-a-digit-in-the-decimal-1-3k5-and-1-3k...

I believe that you are ROUNDING 1.325 to the nearest hundredth to get 1.33

However, the question makes no mention of "rounding."

Given this, we can see that 1.325 is less than 1.33

Does that help?

Cheers,

Brent

## Is long division necessary

## Since you have access to the

Since you have access to the onscreen calculator, you can probably get by without knowing long division.

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