Lesson: Working with Percent

Comment on Working with Percent

I like the idea that one strategy works with all different wordings. Thanks!

"In group 1, there are 300 people, 5% of whom have allergic wheezing and 2% of whom have nonallergic wheezing. That is, (0.05)(300) people, or 15 people, have
allergic wheezing and (0.02)(300) people, or 6 people, have nonallergic wheezing.
Therefore, in group 1, the number of people who have allergic wheezing exceeds the number who have nonallergic wheezing by 9, which is \frac{9}{6}=1.5*100%

The answer is C


I got 250% (not even an answer choice) because I did 15/6 *100 rather than 9/6 * 100. How do you know to do 15/6?
greenlight-admin's picture

You're referring to the question here: http://greprepclub.com/forum/the-number-of-people-in-group-1-who-have-th...

You're mixing up the fact that 15 is equal to 2.5 TIMES 6 with the concept of "greater than".

For example, we can say that 12 is 200% of 6, since 12 = 200% of 6 = 2.00 x 6

However, we can't say that 12 is 200% GREATER THAN 6
To find 200% GREATER THAN 6, we need to ADD 200% of 6 TO 6

That is, 200% GREATER THAN 6 = 6 + (200% of 6) = 6 + (12) = 18

It's best to think of "greater than" in terms of PERCENT CHANGE.

Percent change = (100)(difference if values)/(original value)

So, "x is what percent greater than y?" translates into:

(100)(x - y)/2

The original question is asking "15 is what percent greater than 6?"

So, the percentage = (100)(15 - 6)/6
= (100)(9)/6
= 150%

Dear Brent,

I hope you can clarify two doubts I had when solving these problems :

1. http://greprepclub.com/forum/25-of-1-4-of-x-3575.html

why (1/4)(400)(x) and not (1/4)(1/400)(x) ? (and the same in quantity B)

2. http://greprepclub.com/forum/mary-paid-for-a-book-was-equal-to-the-price-of-the-book-plus-1819.html

why 1.04x dollars and not 0.04x dollars?
greenlight-admin's picture

Link for question 1: http://greprepclub.com/forum/25-of-1-4-of-x-3575.html
Sorry, that was a typo. I've changed it to 1/400

Link for question 2: http://greprepclub.com/forum/mary-paid-for-a-book-was-equal-to-the-price...
If the price of the book is x dollars, then the TOTAL price (including the 4% sales tax) = 1.04x

Here's why:
If the (before tax) price = x, then...
0.04x = the 4% tax
So, the TOTAL price = x + 0.04x = 1.04x

At 7:48 I am trying to solve for P and I can not get 150. If you could work that out please I would appreciate the help!
greenlight-admin's picture

You bet!

We have (p/100)(80) = 120

One approach is to first eliminate the fraction by multiplying both sides by 100 (more on this approach here: https://www.greenlighttestprep.com/module/gre-algebra-and-equation-solvi...)

When we do this, we get: (p)(80) = 12,000

This is the same as 80p = 12,000

Now divide both sides by 80 to get: p = 150

Does that help?

Cheers,
Brent

Thank you!

Can you work out this problem, please?
http://greprepclub.com/forum/geoff-used-630-to-buy-a-new-guitar-this-amount-was-15-perc-1899.html
greenlight-admin's picture

I solved this question as below-
0 < a < b
Quantity A: a% of 1/b
Quantity B: b% of 1/a

Solution:
qty A: a% *1/b
qty B : b% *1/a

qty A : a/100*1/b
qty B : b/100*1/a

qty A: .0a/b
qty B : .0b/a

qty A : smaller numerator/bigger denominator (as b>a given in shared info.)
qty B : Bigger numerator/smaller denominator (as b>a)

so qty B > qty A
Is this approach correct?
greenlight-admin's picture

That solution is fine, but converting a/100 to 0.0a is a little clunky.
For example, if a = 10%, we cannot say that a/100 = 0.010

So, here's what I'd do...

Given:
Quantity A: a% of 1/b
Quantity B: b% of 1/a

Rewrite as:
Quantity A: (a/100)(1/b)
Quantity B: (b/100)(1/a)

Simplify:
Quantity A: a/100b
Quantity B: b/100a

Multiply both sides by 100 to get:
Quantity A: a/b
Quantity B: b/a

Multiply both sides by b to get:
Quantity A: a
Quantity B: b²/a

Multiply both sides by a to get:
Quantity A: a²
Quantity B: b²

If 0 < a < b, then we can be certain that a² < b²
Answer: B

Cheers,
Brent

For that problem, aren't we able to conclude that the answer is B once you got to the below step without having to simplify any further?

Quantity A: a/b
Quantity B: b/a

Given that 0 < a < b
greenlight-admin's picture

You're absolutely right.

If 0 < a < b, then we can be certain that b/a is greater than a/b.
I could have just as well stopped at that point.

Cheers,
Brent

1/16 of 10% of x
How did this become the below?

Quantity B: (1/16)(10)(x)
greenlight-admin's picture

Did I accidentally writhe that somewhere?

1/16 of 10% of x = (1/16)(10/100)(x)

7th question.
i understood now. All this while i thought 1/16 was 1/16% as quantity A had the first part in percentage (25%)
greenlight-admin's picture

Good catch - thanks!
I've changed the 10 to 1/10 here: https://greprepclub.com/forum/25-of-1-4-of-x-3575.html#p7487

Cheers,
Brent

https://greprepclub.com/forum/gre-math-challenge-138-in-a-certain-store-computer-x-costs-796.html
Why isn't the answer D since we were not given the cost of the computer.

In the 2nd question below
https://greprepclub.com/forum/the-change-in-price-of-a-pair-of-shoes-marked-down-by-3062.html
The answer was D becuasue were not given the original price which is the same situation as the first question
greenlight-admin's picture

For the first question, I've added another solution (here https://greprepclub.com/forum/gre-math-challenge-138-in-a-certain-store-...) to show that, even though we don't know the precise costs, we can still conclude that one quantity is greater than the other.

The KEY ASPECT to the first question is that we can express all 3 costs using ONE VARIABLE (z).
This allowed us to compare Quantities A and B.

Question two (https://greprepclub.com/forum/the-change-in-price-of-a-pair-of-shoes-mar...) is much different, because we are unable to express two prices using ONE VARIABLE.

Does that help?

Cheers,
Brent

https://greprepclub.com/forum/17-of-p-is-equal-to-18-of-q-where-p-and-q-are-positive-2308.html#p4320
What makes q less than p
greenlight-admin's picture

Good question.
I've elaborated on my solution here: https://greprepclub.com/forum/17-of-p-is-equal-to-18-of-q-where-p-and-q-...

Cheers,
Brent

Thanks

Why is the denominator 6 in the question below? In my calculations i used 15 but it's obviously wrong. Pls explain
https://greprepclub.com/forum/the-number-of-people-in-group-1-who-have-the-ailment-wheezi-1911.html
greenlight-admin's picture

Question link: https://greprepclub.com/forum/the-number-of-people-in-group-1-who-have-t...

The number of people who have the ailment wheezing (allergic) = 15
The number of people who have the ailment wheezing (nonallergic) = 6

We're asked: The number of people in group 1 who have the ailment wheezing (allergic) is what percent greater than the number of people in group 1 who have the ailment wheezing (nonallergic)?

In other words, 15 is what percent greater than 6?

ASIDE:
In general, we can write the following:
If we're asked "x is what percent greater than y?"...
then the answer is (100)(x - y)/y

So, for this question, we get: (100)(15 - 6)/6

Cheers,
Brent

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