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## Comment on

Circle Properties## Sir the last question from

There is a quadrilateral inscribed in a circle. The diameter is 10. I solved the question using the 2nd and 3rd property mentioned in the video.

2nd property : Inscribed angles holding chords are equal in length

3rd property : Inscribed angle holding a diameter is 90 degree or right angle triangle.

I solved the question by drawing an imaginary line or diameter from point C to A. In this way I got two equal right angle triangles i.e ABC and ADC.

Solving the area for one triangle and then multiplying it by 2, we will get the area for the whole quadrilateral.

Area of triangle ABC : 1/2(BasexHeight)

We know the length of line segment AC ( which is diameter) 10, but we don't know the length of AB and BC.

we can find it by using Pythagorian triple i.e

3-4-5 => 6-8-10

length of AB and BC is receptively 8 and 6.

Area of triangle ABC = 1/2(8*6) = 24

Area of Quadrilateral = 2x24 = 48.

QA>QB therfore A is answer, but the answer is D. I don't understand.

I looked through the explanation, the person kept changing the Quadrilateral shape and size and concluded NO relation can be established. How can he just change the shape and size of Quadrilateral like that? I don't understand the logic. Please help :)

## You're referring to this

You're referring to this question: http://gre.myprepclub.com/forum/the-diameter-of-the-circle-is-3073.html

You made two BIG assumptions in your solution.

First, you assumed that AC is the diameter of the circle, but we can't make that assumption. Sure, it LOOKS like it might be the diameter, but looks can be deceiving :-)

Second, you took a triangle (which you assumed to be a right triangle), and given only one side length (hypotenuse = 10), you concluded that the other two sides must have lengths 6 and 8. This is another incorrect assumption. For example, the 3 sides could have lengths 5, 5√3 and 10 or the 3 sides could have lengths 5√2, 5√2 and 10, and so on.

I hope that helps.

## http://gre.myprepclub.com/forum

can we generalize that, if 4 side polygon inscribed in a circle. Max area covered must be by a square.

## Link: http://gre.myprepclub.com

Link: http://gre.myprepclub.com/forum/the-diameter-of-the-circle-is-3073.html

Yes, we can say that.

## I didn't understand either

## Question link: http:/

Question link: http://gre.myprepclub.com/forum/the-diameter-of-the-circle-is-3073.html

The question doesn't tell us anything about the shape of the quadrilateral. All we can conclude is that ABCD is a quadrilateral that has all 4 points ON the circle - that's it.

Since ABCD is a quadrilateral, it COULD be a square (in which case the area of ABCD is MORE THAN 40).

Or it COULD be super thin rectangle, (in which case the area of ABCD is LESS THAN 40).

For more on the assumptions we can and can't make regarding Geometric diagrams, watch: https://www.greenlighttestprep.com/module/gre-geometry/video/863

## https://gre.myprepclub.com/forum

Wouldn't it be more helpful if it was mentioned whether AB was a cord or not? It says that the figure is not drawn to scale, I was confused whether to assume AB as cord or diameter

## Question link: https:/

Question link: https://gre.myprepclub.com/forum/topic10093.html

AB is definitely not the diameter, but we have to perform several calculations, before we actually know this to be the case.

So, a large part of the question is determining whether AB is the diameter.

Does that help?

Cheers,

Brent

## https://gre.myprepclub.com/forum

Why divide by 8pie-16 by 4

## Question link: https:/

Question link: https://gre.myprepclub.com/forum/in-the-figure-above-if-the-square-inscr...

From Sandy's calculations, we get:

Area of circle = 8π

Area of square = 16

So, the area of ALL FOUR partial circles = 8π - 16

However, the question asks for the area of ONE partial circle.

So, we must divide 8π - 16 by 4.

Cheers,

Brent

## https://gre.myprepclub.com/forum

Kindly solve it Brent

## Here's my full solution:

Here's my full solution: https://gre.myprepclub.com/forum/comparison-of-lengths-of-arcs-2747.html...

Cheers,

Brent

## can the radius be smaller

## Yes, the radius can be

Yes, the radius can be shorter than a chord.

Here's an example: https://imgur.com/lqXPAop

Cheers,

Brent

## https://gre.myprepclub.com/forum

This is one hell of a great exercise!

## Agreed! It certainly has the

Agreed! It certainly has the potential to eat up a lot of time on test day!