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Comment on Consecutive Integers
When you say that every nth
Good question.
Good question.
It doesn't really matter where we start counting. All that matters is that multiples of n appear once every n integers.
That said, if we start from 0, then a multiple of n will appear once every n integers.
I know that 0 is considered
0 is neither positive nor
0 is neither positive nor negative.
So, we can say that 0 is a non-negative integer, or we can say that 0 is a non-positive integer.
Cheers,
Brent
This video was so helpful.
https://gre.myprepclub.com/forum
For this question I realized that in drawing up any 5 consecutive odd integers, and any 7 consecutive odd integers, at least 1 number is divisibly by 3. So couldn't we just look at something that is divisible by 3 and that would land us up at E?
Question link: https:/
Question link: https://gre.myprepclub.com/forum/which-of-the-following-integers-can-be-...
Be careful. Just because one value in a sum may be divisible by 3, that doesn't mean the sum of all five odd integers will be divisible by 3.
For example, in the sum 1 + 3 + 5 + 7 + 9, two of the numbers are divisible by 3.
However, the sum of all five integers is 25, which is not divisible by 3.