Question: 4-Digit Number

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don't you think the 2nd, 3rd and 4th digits should have a probability of 1/9th since the 1st digit cannot be 0 so the following digits cannot be 0 either ? How do we go about this then ?
greenlight-admin's picture

No, it's still 1/10 (although it certainly seems like it might be 1/9).
However, it doesn't matter that the 1st value can't be 0. There are 10 possible values for the 2nd digit, and only 1 of them matches the 1st digit. So, the probability that the 2nd number matches the first is 1/10

For probability approach: Why is the first digit not 9 out of 10 since 0 is not allowed? So isn't 0 not being allowed a restriction for the first digit?
greenlight-admin's picture

We're selecting an integer from 1000 to 9999, so it's impossible for the 1st digit (the thousands digit) to be zero.

Can we imply that the selection of the 2nd to 4th digits is equivalent to "selection with replacement"?
greenlight-admin's picture

Yes, that would be an equivalent model.
Great idea!

Why isn't the probability of 1st digit 1/9?
greenlight-admin's picture

The first digit can be ANY digit among 1, 2, 3, 4, 5, 6, 7, 8, and 9

It doesn't matter which digit it is. What matters is that the remaining digits match the first digit.

Does that help?

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