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Comment on Assigning Variables
Brent-
What was the answer to the final example you gave?
I was trying to work it out and got stuck:
The sum of the three contributions would be:
(1/3)x + 7 + (1/2)x-10 + (1/5)x = x
When getting to common denominators and solve for x:
(10/30)x + 7 + (15/30)x -10 + (6/30)x = (30/30)x
(21/30)x - 3 = (30/30)x
-3 = (9/30)x
x = -10? This is impossible, as the price of the gift should be positive..
I think I went wrong when considering the influence of the constants 7 and -10...
One small problem....
One small problem....
(10/30)x + 7 + (15/30)x - 10 + (6/30)x = (30/30)x
(31/30)x - 3 = (30/30)x [not 21/30x]
Continuing, we get: (1/30)x - 3 = 0
(1/30)x = 3
x = 90
I suggest that you eliminate
I suggest that you eliminate the fractions as soon as possible (for more, see https://www.greenlighttestprep.com/module/gre-algebra-and-equation-solvi...)
Take: (1/3)x + 7 + (1/2)x-10 + (1/5)x = x
Multiply both sides by 30 to get: 10x + 210 + 15x - 300 + 6x = 30x
Simplify: 31x - 90 = 30x
Rearrange: x = 90
for the 4 consecutive odd
Assigning F to the value of
Assigning F to the value of the first odd integer in of itself does not change the value of the first odd integer.
For example, if I tell you that I'm thinking of 4 consecutive odd integers, and you decide to assign F to the first odd integer, that does not change any of the numbers I am thinking of.
Likewise, you COULD say that F+1 = the first odd integer. Once again, this does not change any of the numbers I am thinking of.
The only thing that changes is the way we end up representing the other three numbers.
For example, if we say that F = the 1st odd integer, then...
F + 2 = the 2nd odd integer
F + 4 = the 3rd odd integer
F + 6 = the 4th odd integer
On the other hand, if we say that F+1 = the 1st odd integer, then...
F + 3 = the 2nd odd integer
F + 5 = the 3rd odd integer
F + 7 = the 4th odd integer
In both cases, each subsequent odd integer is 2 greater than the one before it.
Is it safe to say every word
A word equation is never 100%
A word equation is never 100% necessary, but it can definitely help make the transition from words to an algebraic equation.
Hello,
Among the 9,000 people attending a football game atCollege C, there were x students from College C and y students who were not from College C
If we are talking about The number of people attending the game who were not students
It won’t be Y=9000-X?
Thank you
Question link: https:/
Question link: https://gre.myprepclub.com/forum/among-the-9-000-people-attending-a-foot...
Good question.
Your solution would be correct IF it were the case that all of people attending the game who were STUDENTS.
However, we're not told this.
For example, it's possible that the 9000 people are comprised of:
- 1000 STUDENTS from College C
- 2000 STUDENTS who are NOT from College C (i.e., students from another college)
- 6000 people who are NOT students at all
So, in the above example, x = 1000 and y = 2000
So, the number of people who are NOT students = 9000 - (x + y)
Does that help?
Cheers,
Brent
https://gre.myprepclub.com/forum
Hey brent, i'm wondering why the answer isnt 2/3 (34)?
Question link: https:/
Question link: https://gre.myprepclub.com/forum/a-paint-store-mixes-3-4-pint-of-red-pai...
IF the question told us that 2/3 of the paint is comprised of red paint, then the amount of red paint needed to make 34 pints of Perfectly Purple paint = 2/3 of 34.
However, the question is asking us something much different.
Hi Brent - in the Jennifer
J = B + 60
2J = 5B
When we solve it, we get J = 100 (as well as B = 40)
Answer: 100
~thanks a lot
Good question.
Good question.
I added the solution here: https://gre.myprepclub.com/forum/jennifer-has-60-dollars-more-than-brian...
Thanks so much, really
Greetings from Canada!
Greetings from Canada!
James purchased Medicine A
Quantity A
Sales tax paid by James
Quantity B
Sales tax paid by Kate
Hey Brent in this question i have a confusion if james purchased A for x and it includes 5% than i see the amount 'x' = 1.05C but why do we 0.05x/1.05 again he isnt paying 5% twice
Question link: https://gre
Question link: https://gre.myprepclub.com/forum/james-purchased-medicine-a-for-x-dollar...
The pre-tax cost (aka C) equals x/1.05
So, x/1.05 doesn't include any tax (please check out my calculations in my post on GRE Prep Club to confirm that this is the case.)
So, the tax that James pays will equal 5% of x/1.05
Hi Brent, could you help with
For a class of more than 100 students, a teacher has calculated the grades of 100 students, and 22 of those grades were A's. If all of the students whose grades remain to be calculated will receive A's and a total of 25 percent of the entire class will receive A's, then how many students' grades remain to be calculated?
A) 3
B) 4
C) 12
D) 18
E) 26
Given: 100 grades have
Given: 100 grades have already been calculated.
Let x = the number of grades REMAINING to be calculated.
Once the remaining x grades are calculated, the TOTAL number of grades = 100 + x
Since 22 of the first 100 grades are A's, and since the remaining x grades are A's, then the TOTAL number of A's = 22 + x
Finally, since 25% of the entire class will receive A's, we can write: (22 + x)/(100 + x) = 25%
Rewrite as: (22 + x)/(100 + x) = 1/4
Cross multiply: 4(22 + x) = 1(100 + x)
Expand: 88 + 4x = 100 + x
Solve: x = 4
Answer: B
Brilliant thanks Brent.
Make sense now. As got confused and not sure how to assign variable to "more than 100 students" here.
Now I know. Thanks Brent for great explanation always.