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Comment on QC Strategy - Matching Operations
On the next to last example
Plugging in a negative value
Plugging in a negative value for a variable is not the same as multiplying both quantities by a negative number.
with due respect, why not to
That approach can get you
That approach can get you into trouble. If you use the Plugging In Numbers approach, you can't just stop at plugging in one value, since there might be other values of w such that the two quantities are equal or Quantity B is greater (for more on this, watch the part that starts at 2:50 of this video: https://www.greenlighttestprep.com/module/gre-quantitative-comparison/vi...
For example, let's say that we're told that w > 0 and we have the following:
QUANTITY A: w
QUANTITY B: w^2
Using your approach, we might plug in w = 2 (since we're told that w > 0, and 2 > 0). When we do this, we get:
QUANTITY A: 2
QUANTITY B: 4
Here, Quantity B is greater. Does this mean the correct answer is B?
No.
If we plug in w = 1, we get:
QUANTITY A: 1
QUANTITY B: 1
Here, the two quantities are equal.
If we plug in w = 1/2, we get:
QUANTITY A: 1/2
QUANTITY B: 1/4
Here, Quantity A is greater.
So, be careful; plugging in ONE value will not always yield the correct answer.
Also, why not to cancel 'y-3x
We are, indeed, "canceling" y
We are, indeed, "canceling" y - 3x^2 from both quantities. This video is meant to show HOW that works. We do so, by performing the same operation to both quantities.
The term "cancel" can sometimes be misinterpreted. It doesn't mean that, if both quantities share the same algebraic expression, then we can just eliminate those expressions from both quantities.
For example, if we have:
QUANTITY A: 3/x
QUANTITY B: 2/x
We can't just say "Since both expressions have an x term, we just cancel them to get:
QUANTITY A: 3
QUANTITY B: 2
This will yield an incorrect conclusion.
So, we need to be careful to follow the rules/guidelines outlined in the video.
I guess I am confused by the
Good question.
You're referring to the question that appears at 1:37 in the above video:
Given: w > 0
QUANTITY A: 7w + 4
QUANTITY B: w - 2
For Quantitative Comparison questions involving variables, it's often useful to get all of the variables to just one of the quantities. In most cases, that will make it easier to compare the quantities.
Cheers,
Brent
So could I say it is
Are you asking whether we
Are you asking whether we should create the equation 7w + 4 = w - 2?
If so, then the answer is no.
The primary goal of Quantitative Comparison questions is to determine the relationship between the two quantities (Is Quantity A greater? Is Quantity B greater? Do they have equal value?). So, we can never assume that the quantities are of equal value.
Does that help?
Cheers,
Brent
Just to avoid confusion, I
Good point, stomer!
Good point, stomer!
Thank you !!!!
In the reinforcement question
thanks
I'm happy to help!
I'm happy to help!
Question link: https://greprepclub.com/forum/m-p-and-x-are-positive-integers-3017.html
Here's my solution: https://greprepclub.com/forum/m-p-and-x-are-positive-integers-3017.html#...
Cheers,
Brent
I have a question about
Example:
given: x < 0
Quant A: x^3
Quant B: x^5
Can't I divide by x^3 on both sides leaving me with
Quant A: 1
Quant B: x^2
leaving me with answer D?
Aren't I dividing by a negative on both sides?
Should i not do this?
I address this concept at 2
I address this concept at 2:45 in the above video.
However, I'll show you why dividing both quantities by a negative can lead to false conclusions.
Let's say we're asked to compare the following:
QUANTITY A: -6
QUANTITY B: 12
Clearly Quantity B is greater. In fact, if we follow any of the allowable operations, Quantity B will always be greater.
However, if we break one of the rules and divide both quantities by -3, we get:
QUANTITY A: 2
QUANTITY B: -4
Now, Quantity A is greater.
I hope that helps.
Cheers,
Brent
I understand...
So the safe method in the example I provided would be to divide by x^2 instead of x or x^3.
Yes, that would be a safer
Yes, that would be a safer approach.
If we divide both quantities by x², we get:
Quant A: x
Quant B: x³
Now let's test some cases....
CASE I: If x = -1, then we get:
Quant A: x = -1
Quant B: x³ = (-1)³ = -1
In this case, the quantities are equal
CASE II: If x = -2, then we get:
Quant A: x = -2
Quant B: x³ = (-2)³ = -8
In this case, Quantitt A is greater
Answer: D
Cheers,
Brent
So i solved this question can
x - y=5
A: x^2-y^2
B: 5
X^2 - Y^2 can be written as (X-Y)(X+Y), and X-Y = 5. So we get
A: 5(X+Y)
B: 5
Dividing both sides by 5 we get
A: X+Y
B: 1
Let's just deal with one variable so we rewrite the given equation as X = Y + 5 and substitute in A to get
A:5+2Y
B: 1
We do not know whats the true value of Y it can be negative or positive so answer is D.
That's a perfectly valid
That's a perfectly valid solution. Nice work!
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