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Comment on Arranging Buttons
Here can we approach this way
Since total no. of buttons are 6
Red buttons =2
Blue buttons =2
Green buttons = 2
Therefore the no. of ways = 6C2 * 4C2 * 2C2 =90 ways
It took me a while to
It took me a while to determine what you are doing with each step in your solution.
I think I understand now.
There are 6 places each button can go.
So, first we can choose two spaces to place the two red buttons.
We can accomplish this in 6C2 ways.
There are now 4 spaces left.
Next, we'll choose two spaces to place the blue buttons.
We can accomplish this in 4C2 ways.
There are now 2 spaces left.
Finally, we'll choose two spaces to place the green buttons.
We can accomplish this in 2C2 ways.
Great strategy!!!
Cheers,
Brent
Another great approach.
Apology, just dashed
I'm confused because I
Those two questions, although
Those two questions, although similar, have a big difference.
In the books on a shelf question, the books in one topic (e.g, History) are DIFFERENT. For example, one history book might be about the Civil War, which another history book might be about the War of 1812
In the above question, the two red buttons are IDENTICAL, the two blue buttons are IDENTICAL, and the two green buttons are IDENTICAL.
Cheers,
Brent