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Comment on 2x vs. y+2
I divided both sides by 2 and
Quantity A: 2x/2 Quantity B: (y+2)/2
Quantity A: x Quantity B: y/2 + 1
x < y/2 +1
That works also! Nice work.
That works also! Nice work.
Given that - X<Y/2, we can
=> 2x A y+2 B
When 2x is greater than y, y+2 is greater than y,
Then y+2 is greater than 2x.
SO B is greater.
How about this conclusion Brent?
That approach is perfectly
That approach is perfectly valid, Vineet.
in the case of -y 2xgreater
I'm not quite sure I follow
I'm not quite sure I follow your question.
If we take x < y/2 and multiply both sides by 2, we get: 2x < y
Since we also know that y < y + 2, we can combine the two inequalities to get: 2x < y < y + 2, which means the correct answer is B.
Does that help?
After watching you manipulate
That having been said:
1. Manipulate the *given* info one step further than was done in the video:
Given info:
x < y/2
(multiply both sides by 2):
2x < y
(subtract y from both):
2x-y < 0
That is, (2x-y) is negative.
2. Now manipulate the Quantities. Given:
Qty A: 2x
Qty B: y+2
3. Subtract y from both to get:
Qty A: 2x-y
Qty B: 2
4. We know that 2x-y is negative. (Above, 2x-y<0), so we have:
Qty A: something NEGATIVE
Qty B: 2 (= POSITIVE)
Qty B is greater.
That's a perfect solution -
That's a perfect solution - great work!
given x < y/2 (x2 both sides)
Very nice!
Very nice!