Post your question in the Comment section below, and we’ll answer it as fast as humanly possible.

- Video Course
- Video Course Overview - READ FIRST
- General GRE Info and Strategies - 7 videos (all free)
- Quantitative Comparison - 7 videos (all free)
- Arithmetic - 42 videos (some free)
- Powers and Roots - 43 videos (some free)
- Algebra and Equation Solving - 78 videos (some free)
- Word Problems - 54 videos (some free)
- Geometry - 48 videos (some free)
- Integer Properties - 34 videos (some free)
- Statistics - 28 videos (some free)
- Counting - 27 videos (some free)
- Probability - 25 videos (some free)
- Data Interpretation - 24 videos (some free)
- Analytical Writing - 9 videos (all free)
- Sentence Equivalence - 39 videos (all free)
- Text Completion - 51 videos (some free)
- Reading Comprehension - 16 videos (some free)

- Study Guide
- Your Instructor
- Office Hours
- Extras
- Prices

## Comment on

Committee of 2 Men & 2 Women## How is 6C2 =15

## nCr = n!/[r!(n-r)!]

nCr = n!/[r!(n-r)!]

So, 6C2 = 6!/[2!(6-2)!]

= 6!/[2!4!]

= (6)(5)(4)(3)(2)(1)/(2)(1)(4)(3)(2)(1)

= 15

Here's the video that first introduces combinations: https://www.greenlighttestprep.com/module/gre-counting/video/787

Here's a video that shows how to calculate combinations in your head: https://www.greenlighttestprep.com/module/gre-counting/video/789

## I know the outcome of each

## We can still use the FCP, BUT

We can still use the FCP, BUT we need to recognize when to use combinations within our solution.

This is what I have done in the video solution.

We took the task of creating the committee, and broke it into STAGES.

STAGE 1: Select the 2 men

STAGE 2: Select the 2 women

Aside: Notice that the outcomes of each stage are different. In one stage, we are selecting men and in the other stage, we are selecting women. So, we can still apply the FCP.

However, when we get to stage 1, we must recognize that IF we try to break that stage into smaller stages (e.g., select 1 man and then another man),the outcomes are the same. In both cases, we're selecting a man to be on the committee, which means we can't use the FCP. Instead, we must use combinations. That is, we can select 2 men from 6 men in 6C2 ways (15 ways). So, we can complete stage 1 in 15 ways.

The same goes for stage 2 (as in the video solution).

NOTE: If we were to break STAGES 1 and 2 into smaller stages, there is a strategy we COULD use to correct out calculations, but I'd rather not get into it, as it will cause more confusion than it will help.

## Is this not a restriction

## I wouldn't classify questions

I wouldn't classify questions as either restriction questions or non-restriction questions. That will lead to problems.

Also, we can pretty much classify all counting questions as restriction questions. Consider, for example, this question:

"Company X has 8 employees. In how many different ways can we select 3 employees to be on the Party-Planning committee?"

We COULD say that this is a restriction question, because we are restricted to having exactly 3 people on the committee.

Cheers,

Brent

## Okay. Makes more sense now,

## Add a comment