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## Comment on

Divisibility Rules## https://gre.myprepclub.com/forum

please solve brent

## Here's my solution: https:/

Here's my solution: https://gre.myprepclub.com/forum/qotd-18-maria-removed-of-the-cookies-fr...

Cheers,

Brent

## Hi Brent,

In this practice problem, it says that 126 is divisible by 6, which I can see is true. But 9 is not divisible by 2?? SO that doesn't follow the rule, right? I am guessing the number needs to be a certain number of digits long for these rules to apply.

https://gre.myprepclub.com/forum/on-a-weekend-6-college-friends-went-skiing-and-evenly-split-17812.html

## Question link: https:/

Question link: https://gre.myprepclub.com/forum/on-a-weekend-6-college-friends-went-ski...

I think you might be confusing a few divisibility rules.

If a number is divisible by 2, then its units digit must be even (0, 2, 4, 6, or 8)

If a number is divisible by 3, then the sum of its digits must be divisible by 3.

If a number is divisible by 6, then it is divisible by 2 AND by 3

126 has an even units digit (6). So, 126 is divisible by 2.

1 + 2 + 6 = 9, and 9 is divisible by 3. So, 126 is divisible by 3.

Since 126 is divisible by 2 AND by 3, we know that 126 is divisible by 6