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Comment on What Must Be True?
CAN YOU SHOW THIS RESULTS
IF BOTH P AND Q ARE EVEN then p( q-2) (q -1) will solve like this in sections
p* q ( even * even is even right and now this even - 2 ( which is also even) similar add /substract gives even so result is Even. This is multiplied to ( q-1 ) now
result even * q ( which is also even ) gives even , now -1 ( which is odd) from even will give odd
but if we plug values we get even as final ans
We could solve it that way,
We could solve it that way, but I think it will take much longer, since you still have to consider the following 4 cases:
1) p is even and q is even
2) p is even and q is odd
3) p is odd and q is even
4) p is odd and q is odd
Cheers,
Brent
q-1 and q-2 are consecutive
Perfect reasoning!
Perfect reasoning!