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## Comment on

What Must Be True?## CAN YOU SHOW THIS RESULTS

IF BOTH P AND Q ARE EVEN then p( q-2) (q -1) will solve like this in sections

p* q ( even * even is even right and now this even - 2 ( which is also even) similar add /substract gives even so result is Even. This is multiplied to ( q-1 ) now

result even * q ( which is also even ) gives even , now -1 ( which is odd) from even will give odd

but if we plug values we get even as final ans

## We could solve it that way,

We could solve it that way, but I think it will take much longer, since you still have to consider the following 4 cases:

1) p is even and q is even

2) p is even and q is odd

3) p is odd and q is even

4) p is odd and q is odd

Cheers,

Brent

## q-1 and q-2 are consecutive

## Perfect reasoning!

Perfect reasoning!